Using polar coordinates, evaluate the integral so Som x(x2 + y²) dydx. Be careful to check...
2. Sketch the region of integration, and then evaluate the integral by first converting to polar coordinates. 1 V2-x2 (x + y)dydx
5.Use polar coordinates system to evaluate: x2 + y2)dydx , R is the region enclosed by 0 <x< 1 and, -x sy sx
Evaluate the iterated integral by converting to polar coordinates points) | sin(x² + y2)dydx T SHARE Y COMO
3. Draw the region D and evaluate the double integral using polar coordinates. (a) SI x + y dA, x2 + y2 D= {(x, y)| x2 + y2 < 1, x + y > 1} D (b) ſ sin(x2 + y2)dA, D is in the third quadrant enclosed by m2 + y2 = 71, x2 + y2 = 27, y=x, y= V3x.
3. Draw the region D and evaluate the double integral using polar coordinates. dA, D= {(x, y)| x2 + y² <1, x +y > 1} (b) sin(x2 + y2)dA, D is in the third quadrant enclosed by D r? + y2 = 7, x² + y2 = 24, y = 1, y = V3r.
Evaluate the following double integral by converting to polar coordinates. This question requires a graph. 4 V32-x2 3yevz**y* dydx 0 x
please answer both questions
bex Use a double integral in Polar Coordinates to find the area of the rectangular region bounded by x=0,x=1.-O.y-1, HTML Editore BIVA-AIXE 3 1 X X, SE Solve the following double integral using Polar Coordinates. x2 + y dydx HTML Editor
Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA, where R is the region in the first quadrant enclosed by the circle x2 + y2 = 4 and the lines x = 0 and y = x.
3. Evaluate the integral by changing to polar coordinates: SS (x+y) da R Where R is the region in quadrant 2 above the line y=-x and inside the circle x2 + y2 = 2.
1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z.
1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z.