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1) An inductor of 45 mH that has a 2.6 mA current when connected to a circuit. There is a sinusoidal voltage of 12 V applied

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Answer #1

1 → The magnitude of induced emf across the Inductor is, E= L ܘ di dt = ? - = (0.45x1024) 2.3x10-A 12 V = 8.625x10 2 8.63x10-

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