Question

Light with wavelength 500nm is incident upon a surface at an angle of 40.0 degrees, refracts and enters a second medium. The light that enters the second medium travels faster than in the first medium. Compared to properties in the first medium the refracted angle will be (smaller, larger, same), and the index will be (smaller, larger, same), and the frequency will be (smaller, larger, same) and the wavelength will be (smaller larger, same) Angle-larger, index-smaller, frequency-same, wavelength-larger. Angle-larger, index-smaller, frequency-same, wavelength-smaller. Angle-larger, index-smaller, frequency-larger, wavelength-larger. Angle-smaller, index-same, frequency-smaller, wavelength-larger. Angle-smaller, index-larger, frequency-same, wavelength-smaller. O Angle-larger, index-larger, frequency-same, wavelength-larger. Angle-same, index-smaller, frequency-same, wavelength-smaller. O Angle-smaller, index-smaller, frequency-smaller, wavelength-smaller.

Answer 1

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marefagochine inden We know that webcity of light in any malium C- uls - light velocit n faster here given velo elocity of light in second medium Compare than dost medium ni so ig >Y nQ So ngan, Now smaller than index od second medium is angle will be larger. and frequency is always in any is medium Now wavelenth o=frequery a K ولے de de > di V> V So -2 Angle-berger , index-smaller frequency - Same, wavedouch-larger