Question

Consider the word DOG.

a. What would the hexadecimal representation of this word be in ASCII?

b. What would the binary representation of this word be in ASCII?

c. If we rotated the bits that represent this word 8 bits to the right, what would the word become (in letters)?

d. If we rotated the bits that represent DOG 8 places to the left, what would the word become (in letters)?

e. What would the results be (in letters) if we XORed the bits that represent DOG with the hexadecimal value 20 20 20?

f. What would the results be (in letters) if we XORed the bits that represent DOG with the hexadecimal value 07 0E 13?

Answer 1

Following are the ASCII representations of the letters :

• D = decimal 68 = 0x44 = binary 01000100
• O = decimal 79 = 0x4F = binary 01001111
• G = decimal 71 = 0x47 = binary 01000111

a.

Thus, the hexadecimal ASCII representation is :

0x44 0x4F 0x47

b.

Thus, the binary ASCII representation is :

01000100 01001111 01000111

c.

By rotating the word bits 8 bits to the right, the lowest 8 bits will rotate over to the beginning, whle the other bits will shift right.

Thus, the binary ASCII representation would be:

01000111 01000100 01001111

equivalent to ASCII letters

G D O

d.

By rotating the word bits 8 bits to the left, the highest 8 bits will rotate over to the end, whle the other bits will shift left.

Thus, the binary ASCII representation would be:

01001111 01000111 01000100

equivalent to ASCII letters

O G D

e.

Writing 0x20 0x20 0x20 in binary, we get

00100000 00100000 00100000

Also, the binary ASCII representation of DOG is

01000100 01001111 01000111

Upon bitwise-XORing, we get the result as

01100100 01101111 01100111

which is equivalent to hexadecimal

0x64 0x6F 0x67

Writing the corresponding ASCII letters for 0x64, 0x6F, 0x67 respectively, we get the letters

d o g

f.

Writing 0x07 0x0E 0x13 in binary, we get

00000111 00001110 00010011

Also, the binary ASCII representation of DOG is

01000100 01001111 01000111

Upon bitwise-XORing, we get the result as

01000011 01000001 01010100

which is equivalent to hexadecimal

0x43 0x41 0x54

Writing the corresponding ASCII letters for 0x43, 0x41, 0x54 respectively, we get the letters

C A T