4A. given, water at gauge pressure Pg = 3.8 atm
at street level
flows into office building, speed, u = 0.55 m/s
dia of pipe is d = 4.5 cm
at the top floor,
dia of pipe is d' = 2.75 cm
heigth, h = 18 m
now, fron continuity equation
u*pi*d^2 = v*pi*d'^2 [ where v is speed of water at the top of the
building]
hence
v = 0.55(4.5/2.75)^2
v = 1.472727272727 m/s
4B. let the gauge pressure at the top floor be P
then
from bernoullis theorem
Pg + 0.5*rho*u^2 = P + 0.5*rho*v^2 + rho*g*h
P = 3.8*1.01*10^5 + 0.5*1000*(0.55^2 - 1.472^2) -
1000*9.81*18
P = 2.062867*10^5 Pa = 2.042443 atm
P = 2.062867*10^5 Pa
25 10 points Problem 4A Water at a gauge pressure of 3.8 atm at street level...
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