Question

sieve analysis

The results of sieve analysis are as follows: Determine the percent finer than each sieve and plot the grain-size distribution curve Determine D10, D30 and D60 from the grain size distribution curve Calculate the uniformity coefficient and coefficient of gradation Determine the percentages of gravel, sand and fines using the AASHTO system and the USCS.

Answer 1

from graph D10 = 0.09

D30 = 0.2

D60 = 0.4

uniformity coefficient $C_u = \frac {D_{60}}{D_{10}}$

Cu=4.44

coefficient of curvature

, c-D10× D60

Cc=1.11

from graph

garvel size 4.75 mm to 2 mm so , gravel % = 100-95.57=4.43 %

sand 2 mm to 0.075 mm sand % = 95.57-6.23 = 89.34 %

fine less than 0.002 mm = 6.23 %