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a) Construct a frequency distribution where the first class has the limits 0 to <100 b) What is the value of n? The Range? Th

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Answer #1

4)a) n=nunber of classes

Here the number of classes = 3

  • class width=maximun limit - minimum limit/n

=18-0/3=6

class width =6

  • midpoint=(upper limit +lower limit)/2

class1 0-6=0+6/2=3

class 2 6-12=6+12/2=9

class 3 (12-18)=12+18/2=15

b)

0-6 less than 6 but not 0 2 2/11*100=18.18%
6-12 less than 12 but not 6 5 5/11*100=45.45%
12-18 less than 18 but not 12 4 4/11*100=36.36%

5)a)n=number of clases=4

  • class width=maximum limit-minimum limit/n

16-0/4=4

  • midpoint=upper limit -lower limit/2

class1- 0-4=4+0/2=2

class2=(4-8)=8+4/2=6

class 3=(8-12)=12+8/2=10

class 4(12-16)=16+12/2=14

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