A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

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A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

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Answer 1

Answer #1

= According to Ist Law of THERMODYNAMICS o + قيا Δυ heat added to the SYSTEM w work done on the SYSTEM AU- Change in Internal

Also, 1 letm. L) 101.325 J So Work done W = - 747. 27 J 747627 J Capprox) ove sign means work is done & ON SURROUNDING from 1

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Answer 2

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A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

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A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

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A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.

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A gas expands against a constant pressure of 1.25 atm from 12.5 L to 18.4 L. During this process, there is a heat gain by the system of 47.8J. Calculate the energy change of the system.