The federal government of Canada believes that the average response times of emergency response services vary too much across the country. To investigate this, the government obtained independent random samples of 10 response times from each of three large cities. In order to compare the mean response times for the three cities, the data were subjected to an analysis of variance. The results of the ANOVA are summarized in the table below. How would the p-value of the ANOVA F-test be interpreted with α = 0.01?
Degree of freedom | Sqrt Sum | Mean Sqrt | ||
SOURCE | Df | SS | MS | F |
Group | 2 | 0.467 | 0.234 | 0.636 |
Error | 27 | 9.9 | 0.367 | |
Total | 29 |
From the given ANOVA table
Sources df SS MS F
Group 2 0.467 0.234 0.636
Error 27 9.9 0.367
Total 29
the value of F stat is 0.636
From F table , F at 0.01 with df ( 2,27) is 5.488
since F < 5.488 so option C is true
The mean response times differ significantly for the three cities at α=0.01
Thank you for the response!
I have calculated p=0.537153
Since the p-value is greater than alpha 0.01 then the null hypothesis is not rejected. The null hypothesis in this case is that the average response times vary significantly across the country.
If the null hypothesis is not rejected here, what is the answer then?
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