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- 21 For the set of vectors B= let H= span B. 2 13 For y = find the vector in H that is closest to y (note y&H) u N The vecto

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-1 3 2 B = {E -3 3 6:13 3 -2 -4 HE_Span(B) ý = -3 2 5 the matrix consider -1 -3 2 4 4 R2 R₂R, D-32 0 0 -1 - 5 O 3 - 2 - 4 Rg³: رم and let (23-2) those vectors orthogouel. (ا ا-را-) - 8 هيد moke Mare, 8- (-, -, ) حر let . ومد and 2رم ہوم > -رم ركلارام로 (,) umie an orthogonal bet and pan fuse= Храм В So, the closest point to ý ix Now Profigh - 동 4 르 VL 로 일은 • 3+2+5 =0 Ju=(-3물을 ) 12. J 기 기 G=_(-,-2, 4)PLEASE GIVE A RATING IF THIS WAS HELPFUL FOR YOU.

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