Question

Problem The following data were collected from a standard 12 mm diameter test specimen of a magnesium alloy (initial :length( Lo = 30.0mm) 20000 15000 10000 5000 0.0 Load (N) 26500 25000 27000 26500 25000 0.15 0.09 0.06 0.03 0.0 AL (mm) 2.10 2.79 1.50 0.90 0.51 After fracture, the total length was 32.61mm and the diameter was 11.74 mm. Plot the engineering stress- strain curve and calculate

Calculate
The modulus of resilience
The tensile strength
The reduction in area
The elongation
The engineering stress at fracturg
The modulus of elasticity
The 0.2 offset strength

Answer 1

Given load() sl (mm) Sol: O కboo 0.03 10000 0.06 I 5000 0.09 20000 0.) 0.5) 25600 26500 0.90 27000 1.50 Choc 2.79 2070 26 SUO Diameter of specimen (d), >1,27mm stoers (6) - A strain (e) = Al(mm) Loador) stress (1)mme e two units) 1863 Sooo 0.03 44.20 2x103 10000 0:06 88.42 15000 132,63 0.09 8x16? 5x203 Q.15 20000 -176.8y 0.5) 0.017 25000 - 22).04 0.90 0.03 26500 - 234.3 1.50 0.05 27000 - 238.73 26500 - 234 3 0.093 2.79 2.10 -0.07 25000 - 221.04

300 2507 0.2). All out strens -yield strength 100+ SD O2) :2% of ed at 0.01 0.02 003 + OOS 0.06 00€ 8:09 Gut strain stress-strain curve From fignore yield strength = 135 v prosti? goeld strain C.002 a) Modulus R. rusilience 1/2 ( gield streng) (yield strain) 1713570-002 0.135 N/my? 2 Fmare 27000 3) Tensile strength - 퓨야 4 Reduction in oua 2 4-85 700 = 238.73 N / ? Af- AR: (122-11.712) 4.85 m2 % Suduction in area = -4.257. (12) L-D elongation - 32.6) • 2.6) 2-61 % elongation- * 8.7% d) -30 *100 30

OCULOS at Sl:2) e) 2500D From load a stress table fraction engineering stress at fractores 72 - 7 21 (12) = 22)-04 Imore below stress at yield painst corresponding stoain from figure $) Modulus of elasticity 60 Modules of elasticity = 0.001 бохь?»/ww? 3) 0.2 offset Strength = ? From figure 0.2% offset strength is aproximately 190 mm