Question

(5 points) Find the radius of convergence and interval of convergence for the following power series. (-1)" (1 - 1)" (2n-1)2 n=1

Power Series

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Answer 1

(al) E (2-17? (2n-1) 2 series is conve invergent when 11 <1 G.5.11/ch 11a-llca Radine of conve nvergence r=2 Now, Interval of convergence -2 < 2-1 < 2 - 2tlcn < 2+1 -Icn<3 for end point's to cheek series converges or diverges Ž (-10o.(-28 E 2n-1 (2n-1) (2 n=1 this is divergent series es by using p-series Eh, for E n=1 (2n-1) 2A n=1 can-1) alternating series & come convergent Interval (-1,3] or <a s 3 о 1) n=1 x=3 (ر) Å C-10? (220