Mass of the puck, M1=270g =0.270kg
Speed of puck v1=95km/h =95×(1000m/3600s)
v1= 26.39 m/s
Let M2 be the mass of the goalie in kg
Initially the goalie is at rest, v2=0
After goalie catches the puch their combined speed is
v=8.90cm/s = 0.089m/s
Conservation of linear momentum
M1v1+M2v2 =(M1+M2)v
0.270×26.39 + 0 = (0.270+ M2) 0.089
M2 = 79.8 kg
A goalie standing on a frictionless surface catches a 270.0-g puck travelling at 95.0 km/h. After...