Question

Exercise 4 A block is attached to two ropes on opposite sides (m = 20 kg). One rope is wrapped around a bollard (angle of wrap a = 360°) and loaded by a force of S4 = 1000 N. The coefficient of static friction between the rope and the bollard is Moi = 0.2. The coefficient of friction between the block and the ground is Moz = 0.3. Determine the minimum force S3 that is required to keep the block in equilibrium and prevent it from sliding to the left. Hoi S2 Sz Ho2 @ & hp + 11 112 % & ( 3 5 6 00 O E 7 E R O Y G H K 1 3 8 > V С B N M 8 s 01

Answer 1

225.75N

hor S2 M S3 S, - hoz Given S, 1000N mass of angle of woop a: 360 - 20 kg block M = 20 Most 0.3. Mo - 0.2 Since there due loss due to friction to wrapping ha Sa se -0.2 x 2T :) 1000 x =) S = 284.6095433 N

Sr.no FBD Drawing block. of 53 S2 & ling N = Mg Since Efna Szef = $3 17 284.6095 50. Bx 20X9.81 = $3 S3 - 225.7495433N .21 Szł 225.75 N block in so minimum force so acquised to ip keep equilibrium A prevent it from slidin left to is 225.75 N,