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Find the minimum diameter of an l = 19.8 m long copper wire that will stretch...

Find the minimum diameter of an l = 19.8 m long copper wire that will stretch no more than 8.21 mm when a mass of 399 kg is hung on the lower end. (Hint: The Young's modulus of copper is 110.0 GPa.)

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Answer #1

We know that, Y = ( ) ( AL) A = A d2 0.785a2 y = ( ) / (AL) lox log Oo82) 399 x 9.8 0.78502 > a = 0.01045 m d = 1.045 cm d =

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