C----------------> D + E
I 1.111*10^-2 1.111*10^-2 1.111*10^-2
C +x -x -x
E 1.111*10^-2+x 1.111*10^-2 -x 1.111*10^-2 -x
Kc = [D][E]/[C]
7.755*10^-5 = (1.111*10^-2-x)(1.111*10^-2-x)/(1.111*10^-2 + x)
7.755*10^-5*(1.111*10^-2 + x) = (1.111*10^-2-x)(1.111*10^-2-x)
x = 0.00984
[C] = 1.111*10^-2 +0.00984 = 0.02095M
[D] = 1.111*10^-2 -0.00984 = 0.00127M
[E] = 1.111*10^-2 -0.00984 = 0.00127M
The equilibrium constant K, for the reaction below is is 7.755x10 CD+E 1st attempt See Periodic...
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