Question

e chemical equation for the dissociation of HCIO2 in water is: HClO2(aq) = H(aq) + CO2(aq) K = 1.1 X 10-2 are the equilibrium concentrations of HClO2(aq) and CO2 (aq), and the pH of a 0.1 M solution? a. 0.064 M, 0.036 M and 1.19 b. 0.072M, 0.028 M and 1.55 c. 0.067M, 0.032 M and 1.50 d. 0.072 M, 0.028 M and 1.14 e. 0.067 M, 0.033 M and 1.48

Answer 1

classmite | Hdą = + do kae. 1.1x10* 0.jm__400 cum wo a decreases from 0.1.11 - hence [ut]: x 0.1-a a at faolt Ka= [ht] [ do, ] [Hito, ) =0. fiato HX10 *** 0.1-a *--HX1023_-7.txront M + 0.0112 - 0.0011 = 0 Solving quadratic we get X=0.0.283 m Hence [ht] = 0.0281 M fecto,] = 0.0881m [Helo) = 11-0.0281 0790072M pH = -log[MT] = -log (0.0281) R Hence of them © is correct.