The first has one server and no limit on the length of the queue. Customers arrive...
Customers arrive at a service facility with one server according to a Poisson process with a rate of 5 per hour. The service time are i.i.d. exponential r.v.´s, and on the average, the server can serve 7 customers per hour. Suppose that the system is in the stationary regime. (a) What is the probability that at a particular time moment, there will be no queue? (b) What is the probability that a particular time moment, there will be more than...
For the following problems compute (a) utilization, (b) average time a customer waits in the queue, (c) average number of customers waiting in the queue, (d) average number of customers in service, (e) the average time a customer spends in the system. Problem 1. An average of 10 cars per hour (with variance 4) arrives at a single-server drive-in teller. Assume that the average service time for each customer is 5.5 minutes (with variance 5). Problem 2. Customers arrive to...
Automobiles arrive at the drive-through window at the downtown Baton Rouge, Louisiana, post office at the rate of 2 every 10 minutes. The average service time is 1.5 minutes. The Poisson distribution is appropriate for the arrival rate and service times are negative exponentially distributed. q: If a second drive-through window, with its own server, were added, the average time a car is in the system = nothing minutes (round your response to two decimal places).
Suppose vehicles arrive at a single toll booth according to a Poisson process with a mean arrival rate of 8.4 veh/min. Their service times are exponentially distributed. The mean processing rate is 10 veh/min. a. What is the value of the utilization ratio? b. What is the average length of the queue? c. What is the average waiting time in the queue? d. What is the average time spent in the system?
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2. Customers arrive to a coffee cart according to a Poisson process with constant rate 12 per hour. Each customer is served by a single server and this takes an exponentially-distributed amount of time with mean 2 minutes irrespective of ev- erything else. When the coffee cart opens for service, there are already 7 people waiting. Denote by X = (X+,t> 0) the number of people waiting or in service at the coffee cart t hours...
roblem Consider a single server queueing system where the customers arrive according to a Poisson process with a mean rate of 18 per hour, and the service time follows an exponential distribution with a mean of 3 minutes. (1). What is the probability that there are more than 3 customers in the system? (2). Compute L, Lq and L, (3). Compute W, W and W (4). Suppose that the mean arrival rate is 21 instead of 18, what is the...
Consider the following parameters for a queueing system with an infinite queue and infinite calling population. Arrivals follow the Poisson distribution with an average rate of 12 per hour. Service times are exponentially distributed with an average time of 4 minutes. Find the set of queue statistics (N, Nq, T, Tq, r), and find the percentage of time that the server is busy.
4. (25 points) There are two servers, server 1 and server 2, that serve customers with exponential service rates 1=2 and 2=3 respectively. Customers arrive according to a Poisson process with rate =1. An arriving customer first enters server 1 if the server is free. If server 1 is busy when a customer arrives the customer leaves the system and a cost of 10 TL is incurred. A customer who has received service from server 1 then moves to server...
Problem 8: 10 points Consider a queuing system M/M/1 with one server. Customer arrivals form a Poisson process with the intensity A 15 per hour. Service times are exponentially distributed with the expectation3 minutes Assume that the number of customers at t-0, has the stationary distribution. 1. Find the average queue length, (L) 2. What is the expected waiting time, (W), for a customer? 3. Determine the expected number of customers that have completed their services within the 8-hour shift
Customers arrive at Rich Dunn's Styling Shop at a rate of 2 per hour, distributed in a Poisson fashion. Service times follow a negative exponential distribution, and Rich can perform an average of 5 haircuts per hour. customers (round your response to two decimal places). a) The average number of customers waiting for haircuts = customers (round your response to two decimal places). b) The average number of customers in the shop = c) The average time a customer waits...