Question

A golf ball is given an initial velocity of 60 m/s at an angle of 40∞ above the horizontal. The fairway slopes down at a constant angle of 10∞ away from the tee. (It is simplest to place the tee at x₀ = 0, y₀ = 0.)

How far from the tee, measured along the fairway, will the ball land?

Answer 1

The ball will move in a projectile motion As we know that fairway is slopes down at an angle of 10. So we first find the range of the ball in the horizontal plane and by applying trigonometry we find the actual distance b/w & where ball lands. So the Range for projectile motion is defined as R = u^2 sin 20/g u = 60 m/s theta = 40 = (60)^2 sin 2 times 40/9.8 = 3600 times 0.98/9.8 R = 360 m So now we find the actual distance by applying cos theta. Cos theta = B/H = R/R_actula theta = 10 degree cos 10 degree = 360/R_actual R_actual = 365.55 m Ans