Question

Mass M1 = 4 kilograms is suspended on a massless frictionless pulley and is connected with a massless rope to Mt = 2 kg, a mass on a frictionless table. Mt is attached to another suspended mass M2 = 6 kg with a massless rope over a massless frictionless pulley. (diagram attached)

Find the velocity of each of the masses when M2 falls 20 cm. What is the acceleration of the system?

DE

Answer 1

a Me Tz A Tz 42

het the acceleration is a Net force on m o E F = m₂ g -T2 ma = mg - Tz .: T2 = magamza Wet force on my EF = Timig ma=ti-mg 1 - м, а + мач — 0 het force on me [ F = Tq - Ti ma = T2 - To value of T, and to put by equ6 and me a = (mg-m2a)-(m, at mig) n a mag-mig g (me-m,) m, the tmz mit matt - 9 = (9.60ms) (6 kg - urg) u kg + 6 kg + 2kg a = 1.63 m/s2 - Answer 1 final velocity after to travel distance d=900m = 0.40m - viz +2 ad vp = 0 + P11063m152) 10.20m) VF=0.bimis? ------ Aus wel