Question

Consider the circuit shown below. Resistors A=10 Ohm, C=20 Ohm, and D=30 Ohm. The batteries B=6V, E=12V, and F=20V. Calculate currents in the circuit. E n

Answer 1

Given circuit - F=20v E=12V I, R. o I 3 th + T 1 3 I. Y2 3 A=100 c=20$ www D=302 t1 B=6V current Since Kirchhoff 18 how states that current flowing into a junction junction must be equal to cumbent flowing out of it at the junction a sa I = It Is eq and Kinchhochs Voltage low states that the sum of all Voltage around any in a circuit equal zero. closed loop must

مگر in the loop ORQP. D 2 -12 +10 I+ 6 + 20 I 10 I, 720 IZ = 6 eq in the loop OTSP and 20 30 I IB + 20 I 201_-30 Iz = 200 cm putting the value f I = I, - Iz in in above equation - 201_- 30 (1,-1) = 20 - 30 I +50 I = 20 2 6- 20 Iz in above value of I 10 putting the equation -30 t 6- 20 Iz 10 +50I, 50 I2 = 20 18 + 60 Iz +50 I =20 2 110 Iz = 38 38 In - Amp

D I 0.345 Amp HA of Iz 2 putting this value in eq lo I +20 (0.345) = 6 10 I, 6 -6.9 0.9 I Amp to I. = 0.og Amp here negative sigh shows that direction of cunnent' In will be opposite poom given diagram putting the values of I, and Ig in eq 0 - 0.345fI +7 3 > I I, = 0.09 -0.345 Amp >> 3 =-0.435 Amp of here negative sign shows that direction current I must be Opposite from given direction of Iz in diagram