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3. An electron at point A has a speed of 5x106 m/s. Find the value and...

3. An electron at point A has a speed of 5x106 m/s. Find the value and direction of the flux density of the field that will cause the electron to follow the semi-circular path from A to B . The distance from A to B is 40 cm. Please explain.

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Answer #1

AB = diameter of path = 2r = 2mv/qB

=> 0.40 = 2 x 9.109 x 10-31 x 5 x 106/(1.602 x 10-19 x B)

=> B = 1.4215 x 10-4 T

Direction will be such that if v is the initial velocity then direction of B should be such that the direction of vXB should point in direction from B to A.

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