Question

ek 5 Quiz Question 7 Find the area to the right of the z-score 1.40 and to the left of the z-score 1.58 under the standard normal curve. z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 1.3 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 0.9177 1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319 1.5 0.9332 0.9345 0.9357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 0.9441 1.6 0.9452 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 0.9545 1.7 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 0.9633 1.8 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9699 0.9706 1.9 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767 Use the values) from the table above.

Answer 1

Solution:
We need to calculate
P(1.40<Z<1.58) = P(Z<1.58) - P(Z<1.40)
From Z table we found p-values as shown in figure
P(1.40<Z<1.58) = P(Z<1.58) - P(Z<1.40) = 0.9429 - 0.9192 = 0.0237

So the area to the right of the z score 1.40 and to the left of the z score 1.58 or we can see in b/w of 1.4 and 1.58 is 0.0237 or 2.37%