A 34 m tall building casts a shadow. The distance from the top of the building...

Question

Question

Answer 1

Answer #1

by Pythagorean theorem, lengin of shadow ✓ (37) ² (34) ² the 71 X 3 - 213 m 14.59 m = 14.6 m (ne nearest tenth)

Answer 2

Similar Homework Help Questions

A pole that is 3.2 m tall casts a shadow that is 1.58 m long. At...

A pole that is 3.2 m tall casts a shadow that is 1.58 m long. At the same time, a nearby tower casts a shadow that is 4425 m long. How tall is the tower? Round your answer to the nearest meter. x 6 ?
Devin v O GEOMETRY Indirect measurement A pole that is 3.2 m tall casts a shadow...

Devin v O GEOMETRY Indirect measurement A pole that is 3.2 m tall casts a shadow that is 1.29 m long. At the same time, a nearby tower casts a shadow that is 39.25 m long. How tall is the tower? Round your answer to the nearest meter. TI ? X Check 2020 McGraw-Hill Education. Al Rights Reserved. Terms of Use | Pvc Explanation 18
Heather is 1.74 meters tall. One day, she casts a shadow that was 2.14 meters long....

Heather is 1.74 meters tall. One day, she casts a shadow that was 2.14 meters long. At the same time, a tree casts a shadow that was 8.44 meters long. Find the height of the tree in meters, to the nearest two decimal places. Make sure that your answer has exactly two decimal places. h 1.74 m 2.14 m 8.44 m The height of the tree is 16.88 X meters.

• (5pts) A man 6 feet tall is walking away from a building that is 24...

• (5pts) A man 6 feet tall is walking away from a building that is 24 feet high. There is a light at the top of the building that casts a shadow of the man onto the ground. If the man is walking at a rate of 7 feet per second, at what rate is the tip of his shadow moving when he is 12 feet away from the building?
1. The angle of elevation to the top of a very tall Building is found to...

1. The angle of elevation to the top of a very tall Building is found to be 8° from the ground at a distance of 1 mi from the base of the building. Using this information, find the height of the building. (Round your answer to the nearest foot.) _______ft 2. A 19-ft ladder leans against a building so that the angle between the ground and the ladder is 71°. How high does the ladder reach on the building? (Round...
A tree on a hillside casts a shadow c ft down the hill. If the angle...

A tree on a hillside casts a shadow c ft down the hill. If the angle of inclination of the hillside is b to the horizontal and the angle of elevation of the sun is a, find the height of the tree. Assume a = 57°, b = 27° c = 215 ft. (Round your answer to the nearest whole number.) 73 X ft b

From the top of a 20 m tall building (its a two story building) you throw...

From the top of a 20 m tall building (its a two story building) you throw a rock, releasing it at a height level with the top of the building and with the rock going 6.0 m/s at 30 ° below the horizon- tal. What is the y-component of the velocity of the rock when it reaches a speed of 12 m/s, and how high above the ground is it at that instant? Answer is -11m/s and 14 m, but...
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft...

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ft!s along a straight path. How fast is the tip of his shadow moving when he is 40 ft from the pole? The answer is 25/3. I let x be the length of shadow, y be the distance between man and pole. I did 6/15=x/(x y) then i got x=2/3y dx/dt=dy/dt(2/3) Then I...
13. A 0.04-kg ball is thrown from the top of a 30-m tall building (point A)...

13. A 0.04-kg ball is thrown from the top of a 30-m tall building (point A) at an unknown angle above the horizontal. As shown in the figure, the ball attains a maximum height of 10 m above the top of the building before striking the ground at point B. If air resistance is negligible, what is the value of the kinetic energy of the ball at B minus the kinetic energy of the ball at A (KB - KA)?...

An object, at the top of a very tall building, is released from rest and falls...

An object, at the top of a very tall building, is released from rest and falls freely due to gravity. Neglect air resistance and calculate the distance covered by the object between times t1 = 4.12 s and t2 = 6.27 s after it is released.