Question

Assume the channel bandwidth is 3100 Hz and the maximum data rate is 35 kb/s. To improve the maximum data rate by 60%, how many times should the signal-to-noise-rate (SNR) increase? Based on the improved maximum data rate and SNR, if the SNR further increases by 10 times, can the maximum data rate further increase by 20%?

Answer 1

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ginen, Band Width - 3100 Hz - 3.11. Hz Max. Bit rate (08) date Rate = c = 85.kbls We know, 1 (= Bloga (lt ) 2 = leg, (it) 05719), - -(5)- ), -2503-5 (5) = 2501-5) Now, given, e increased by 60% - Cnew = c + 60%.C = c(1460) Knew = 1.60] let, I will increase by at [Cnew = 58 k bls] - (now - (1) + (3) rahew - (35) (1) hew = 2503–5 (145) Chew from ey O is, 1 (new = 25035 (v + a) . plannel 109.5 g it in the 2503.5 ) X = 100 x 108.5 a = 107.5 -1 x= 10850 - SNR will increas 10850 %.

a new = 2503.5. (e+ 1060) = 244133:25 109.5 new 274133.25 () new = 274133.25 + 2003.5 → SNR increased by 109.5%, wow, (3) new is further increase line na to times * Www = 274133.25 x 10 = 2741332.5 DVD o Coewe = o kog 2 (1+ Chhew) 3.1k losz (14 2741235) - Finewo = 66.3 kb/sec Chewo = Chew + 20 Chew = new ( 1+200) = 1.2 x 58 x ble .. . Theme = 67.216 ble]> 0 since ® 2 , we can say that thewe is increased further by almost or near to 20%

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