Question

86.50mL of a concentrated ethanol solution is added to a container to make 1.75 L of a 0.070 M diluted solution. what was the initial concentration of the ethanol?

1 This is a Numeric Entry question/it is worth 1 point/You have unlimited attempts/There is no attempt penalty 02 Question (1 point) See page 325 1st attempt lul See Periodic Table See Hint 86.50 mL of a concentrated ethanol solution is added to a container to make 1.75 L of a 0.070 M diluted solution. What was the initial concentration of the ethanol? SUBMIT ANSWE < 02/07 > 1 OF 7 QUESTIONS COMPLETED MacBook Pro

Answer 1

For solving these problems, you will have to use dilution equation.

M1V1 = M2V2

M1 is Molarity of solution with volume V1

M2 is Molarity of solution with volume V2

First the volumes need to be converted into Liter.

Initial volume = 86.50 mL

For converting into liters we need to divide by 1000

Initial volume = V1 = 86.50/1000 = 0.0865 L

Initial concentration = M1

Final concentration = M2 = 0.070 M

Final volume= V2 = 1.75 L

M1 x 0.0865 L = 0.070 M x 1.75 L

M1 = 1.416 M

So initial concentration was 1.416 M