VR = IR ----------(1)
VL = IXL -------------(2)
VC = IXC -----------(3)
Xc = Vc/I
I = VR / R from equation (1)
XC = Vc / (VR / R)
XC = R( Vc / VR )
XL = VL/ I
XL = VL/ VR / R
XL = R( VL / VR )
1. Through Ohm's Law, we know that VR-IR and V1 = IX and Vc = IX....
1) Please derive equation 2 from Ohm's Law knowing that the
current is the same through each element in a series circuit.
Please derive equation 3 from Ohm's Law knowing that the potential
difference is the same across each element in a parallel
circuit.
R = R + R2 + R + ... 1.1+1+1+... RyRRER
The voltage drop (V) across a resister is proportional to the current (I) through the resister. Ohm's Law: V = IR. Wednesday's laboratory expernnent attempts to verify Ohm's Law and measure the resistance (R) of a resister Ammeters and voltmeters potentially have offsets, resulting in a constant added to the equation: V = IR + VO If voltage satisfying this equation is plotted against current, the result is a line. With voltage on the y-axis and current on the r-axis,...
1)
2)
3)
Using Ohm's Law, the answer for 2 is: (don't need an answer for
number 3)
4)
R1 V. + R2 12 R3 https://drive.google.com/file/d/1WJUWDo8q7wGCQmwBgMvR04B_SY-MNJNN/view?usp=sharing Consider the circuit in Figure 2. We will assume that both the power supply's potentials V and V, along with the resistors R, through R3 are known quantities where the currents flowing through the circuit are unknown. Since there are three unknown currents in this circuit, three linearly independent equations are needed in order...
Help fill in table
The CH2 waveform vr(t) is shown in red. 3. Now, double the function generator frequency (to f=1250Hz about 1250Hz) to display exactly two complete cycles in 8 horizontal divisions. Do not change the amplitude of e(t). Again, both waveforms should be centered vertically on the scope grid. Adjust the vertical POSITION knobs if necessary. Carefully sketch and label both waveforms on the grid. Use the same settings (VOLTS/DIV AND SEC/DIV from part A4.) as with the...
REP (L/A); R = Ro (1+AAT); Ohm's Law: AV = IR: Area of a circler?:p - Po (1 + QAT); Fe =qvB sine ;FgqvB; F. (mv)/r; B - Mol/127V): 40 - 4m x 10 T.m/A; Series: Rnet = R1 + R2 + R3; Parallel: Rnet = ((1/R1) +(1/R2) + (1/R3)) ? : You are working in lab was given a task by your supervisor to determine the density of a material which he wanted use in a circuit. Material he...
Procedure Table 1 Voltage Generated, v Voltage across R, VR (V) Current IR, (A) 1 V 0.194 0.021 2 V 0.393 0.041 3 V 0.593 0.061 4 V 0.794 0.081 5 V 0.995 0.101 Average 0.593 0.061 Procedure 2 Setup Procedure Procedure 2 Setup Procedure Table 2 Voltage Generated, v Voltage across R, VRC (V) Voltage across C, Vc (V) 1V 0.161 0.526 2 V 0.322 1.052 3 V 0.489 1.586 4 V 0.651 2.109 5 V 0.816 2.647 Average...
2-a)-RLC components connected in series in a circuit supplied by a variable dc voltage can be described by the following differential equations: di(t) wherei@ is the loop current and V1(t) İs the voltage drop across the inductor.+' The voltage drop across the resistor is given by Ohm's law vR(t) R i(t) and the voltage drop across the capacitor vc(t) is given by i(t) dt For a series circuit ye)t vit)t velt) v(t) where v(t) is applied voltage: Figure 3: RLC...
11. Since Analog Discovery can only measure voltage, we have to use Ohm's Law to calculate the input current to the circuit (LAB), then calculate total resistance. For the circuit in Fig. 1, connect resistor (Rs - could be any value - for example Rs - 1k) in series with the voltage source (5V) as shown below and use Analog Discovery Voltmeter to measure the voltage across Rs. Then the input current lab (from A to B)= VR/Rs. Measure the...
Question 1 8.75 pts Ohm's law states V = IR, Voltage = Current x Resistance. If a toaster has a resistance of 60 ohms and is plugged into a 120 volt outlet, how much current will it "draw"? O 5 Amps O2 Amps O 0.5 Amps 1 Amp Question 2 8.75 pts The atomic nucleus is most often made up of protons protons and neutrons Fermions neutrons electrons
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V=220V, and the frequency is f=170πHz. Given that L=0.7H, C=20μF, and VR=10V(rms). Since everything is stated and asked for in rms you never need to do a conversion with the square root of 2. Find: a) I (rms); I= A This will involve some algebra since you are not given R. I suggest you start by calculating the inductive and capacitive reactances. b) R;...