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A charge 91 = 3.22 UC is at a distance d = 1.13 m from a second charge 92 = -5.47 uc. 92 (a) Find the electric potential at a

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Ans q=322uc 9 = -5.47 uc d/ d/2 d = 1.13 m We know At point A d/ u electric potential f = kg, electric potential diet a, =T i l let poput B electric potential is zero. a B qz (da) (da) V = 1 + 2 = 0 VB = kal & k22 = 0 = kx ( 3:22 x179 - sun xo) =

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