Question

312: A 35 hp pump operates at steady state and is adiabatic and internally reversible. At the inlet the pump has a flow area of 0.04 m² and draws in 52 kg/s of liquid water at 1 bar, 20 °C. At the exit the water is at 4 bar, 15 °C with a flow area of 50 cm. What is the maximum elevation, m, of the pump exit compared to the pump inlet?

Answer 1

2 soli Given work input to Pump w = -35hp (cork done on) = 6 --26.0995 kW as I hp = 0.745 7. kW. Area at inlet (A) = 0.04 m2 Area at exit (A2) = 0.05 m² Also mass flow rate is 52 kg/s. Inlet Conditions of water. Outlet Condition of water- P = qbar P2 = 4 bar. Ti = 20°c = 293% Tz = 15°C - 288k Also from Steady flow energy Equation, we have in (hout a hint out - Vin + g (Zout-Zin) = 8-w hout, hin are enthalapy at exit and inlet. Vout, Vin are fluid velocity at exit and inlet- Yout, zin are elevation at exit and inlet. ď heat input rate to (Adiabatic). w work input. & in is mass flow rate. » SFEE becomes. in (hout -hin + Vaul - Vin? + g(lout - Zin) = -6. also th= G (92-5). for water 6 = 4.18 w ligh Vins et (004) = 1.3 m/s & Vout s a 104 - PAZ 52(4.181-5)+ (1.09% (1.93 27 3-81(02)) = 26.0995, - 2110o). 20.9+(-0.0003) + 9.81 oz 1000, -0.502 a) oz - 20398 - 2079 m. 981