Question

statics

Q1) The opposite figure has a triangular part of density p=4.9 kg/m, and a quadrant of p=9.8 kg/m.for a=1.5 m and b=8 m, the mass of the total shape is: A. 407.16 B. 1301.15 C.522.00 D. 271.44 E. 689.04 The opposite figure has a triangular part of density p.=4.9 kg/m., and a quadrant of pa=9.8 kg/m.for a=1.5 m and b=8 m, X A. 2.43 3.4.68 C.6.17 D. 3.65 E. 7.57 The opposite figure has a triangular part of density p=4.9 kg/m., and a quadrant of p:=9.8 kg/m.for a=1.5 m and b=8 m, Y-= A. 3.35 B. 12.14 C.4.09 D. 11.14 E. 8.45 The opposite figure has a triangular part of density p=4.9 kg/m, and a quadrant of p:=9.8 kg/m.for a=1.5 m and b=8 m, la for the triangle is A. 476.67 B. 82163 C. 727.55 D. 68.99 E. 313.60 The opposite figure has a triangular part of density p.=4.9 kg/m, and a quadrant of p=9.8 kg/m.for a=1.5 m and b=8 m, la for total shape is A. 8195.23 B. 12456.75 C. 19012.93 D. 1802.95 E. 21471.50 The opposite figure has a triangular part of density p.=4.9 kg/m, and a quadrant of pe=9.8 kg/m2. for a=1.5 m and b=8 m, In for total shape is A. 8705 B. 4493 C 24992 D. 6739.53 E. 14041 The opposite figure has a triangular part of density p=4.9 kg/m, and a quadrant of pe=9.8 kg/m. for a=1.5 m and b=8 m, Iwfor the triangle is A. 54 B. 44 C. 33 D. 17.20 E 26

Answer 1

Solution 0 Given That = 4914 12 = 9.8kg m2 m2 a=1.5 b=8 Total mass (m) = f A + f Az ma tiga 1 a Kb + 918X II (6.)? 2 m= 4.9 & 1 x 11508 + 9.8 * I x( 812 4 m = 522.00 Kg Answers obtion @ 522.00 kg (99 (4+4) 31/ exut e hu = 5 (4.969b)x(39)+(9:8427 2. X mi tm2 ma + m₂ ac z 4.918x1.5xZ1:5 +98475 (852x61.54 (1:54 445) 3T 522.00 M 89.5 = x From orign Ang B) 4.68m14

ac Yez m.Y + M2 42 mt m2 2 8. x/4x8 Yea (4. (944x1545)x(3) +(Bisy ) 3 3 T 522:00 o' Y = 3.55m Ane from origin option À 3.35 m C Q@ Inn for Traingular part A NA Tocamb² 18 b | parallel tais Theorem I =IGG + m (K) 2 Lan= 29.4*82 1.8 + 2914 A ( 312 Inn = 313.60 kg-m 2 34 Are mk2