What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H302 (82.0 g/mol),...

Question

Question

What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H302 (82.0 g/mol), in water? The density of the solut

Answer 1

Answer #1

$Molarity=\frac{moles}{volume (litre)}$

% by mass of solution = 17 % i.e. 100 gram of solution contains 17 gram of sodium acetate.

Thus, volume of solution (100 grams) = $\frac{mass}{density}=\frac{100}{1.09}=91.743ml = 0.0917 litre$

Moles of sodium acetate (17 gm) = $\frac{mass}{Molar mass}=\frac{17}{82}=0.207$ moles

Thus, $Molarity=\frac{moles}{volume (litre)}=\frac{0.207}{0.0917}=2.257 M$

Answer is 2 i.e. 2.26 M

Answer 2

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