Consider the following equilibrium reaction: C3H8 (g) + 5O2 (g) -> 3CO2 (g) + 4 H2O...
Consider the following equilibrium reaction:
C3H8 (g) + 5O2 (g) -> 3CO2 (g) + 4 H2O (l) delta H = -2220KJ
if the amount of H2) is reduced to the system, the CO2
concentration increases.
select one:
a) Right
b) False
Homework Answers
The H2) will most probably be H2O i hope.
Enthalpy negative means that system release heat to the surrounding. Since H2O is removed from the system ,being one of the product, the equilibrium shifts towards the pdt side (lee chatliers principle) and so more CO2 will be produced. So answer is right.
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Consider the following equilibrium reaction:
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4. Consider the following reaction at equilibrium CO(g) + H2O(g) + CO2(g) + H2(g) 2.50 mole of CO(g) and 2.50 mole of H2O(g) gas at 588 K are mixed in a 10.00 L container. (Kc = 31.4 at 588 K) Calculate the concentration of CO(g), H2O(g), CO (g), and H.(g) at equilibrium. 5. Consider the following reaction: CO(g) + H2O(g) + CO2(g) + H2(g) (a) If a 10.00L container has 2.50 mole of CO(g), 2.50 mole of H2O(g), 5.00 mole...
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