Consider the following reaction:
C3H8+5O2→3CO2+4H2OC3H8+5O2→3CO2+4H2O
What is the reducing agent?
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Consider the following reaction: C3H8+5O2→3CO2+4H2OC3H8+5O2→3CO2+4H2O What is the reducing agent? C3H8C3H8 CC OO O2
The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 7.5 mol of O2 with 1.4 mol of C3H8 will produce ________ mol of CO2. Group of answer choices.
C3H8 _ o2 ~3CO2 + 4H2O which of the following balances the reaction above? -1 -5 -3 -7
Please help? Calculate deltaHr for the reaction: C3H8(g) + 5O2(g)----->3CO2(g) + 4H2O(l) Given: 3C(s) + 4H2(g)----->C3H8(g) deltaH -24.8 kcal H2(g) + 1/2 O2(g)----->H2O(l) deltaH -68.3kcal C(s) + O2(g)-------> CO2(g) deltaH -94.0 kcal
Propane (C3H8) burns in oxygen to produce carbon dioxide and water via the following reaction: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 49.9 g of propane and sufficient oxygen has a 60.0 % yield.
If we have C3H8 + 5O2 ---> 3CO2 + 4H2O a) How many liters of oxygen gas are required to react with 7.2 L of C3H8 if both gasses are at STP? b) How many grams of CO2 will be produced from 35 L C3H8 at 15 C and 1.65 atm? c) How many grams of water vapor can be produced when 15 L C3H8 at 15 C and 1.65 atm are reacted with 15 L O2 at -20.0 C...
Consider the combustion of propane: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O(l) ΔH = –2221 kJ Assume that all of the heat comes from the combustion of propane. Calculate ΔH in which 5.00 g of propane is burned in excess oxygen at constant pressure.
The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) C3H8 (g)= -104.7 CO2(g)= −393.5 H2O(g)= −241.8 Calculate the enthalpy for the combustion of 1 mole of propane.
The combustion of propane may be described by the chemical equation C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g) How many grams of O2(g) are needed to completely burn 70.9 g C3H8(g)? mass O2: g O2
Propane (C3H8)burns according to the following balanced equation: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calculate ΔH∘rxnΔ for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/molkJ/mol.) Express the enthalpy in kilojoules to four significant figures.
calculate the enthalpy of the combustion of propane for your barbeque C3H8 + 5O2 -> 3CO2 + 4H2O propane -105 kJ/mol CO2 -394 kJ/mol Water -286 kJ/mol Ooxygen. 0