Protonated and deprotonated form of amino acid depend on the pH and pKa value. If pH value is greater than the pKa the ionizable group loses its proton and remains in deprotonated form. In this peptide there are four ionizable groups two of the peptide chain, amino and carboxy terminal which are not involved in peptide bond formation and other two are side chain of the amino acid, aspartic acid and lysine.
Ans d- at pH 7.4 the charge can be calculated as
the COO- group of the C terminal (pKa= 2.34) and aspartic acid (pKa= 3.86)present in deprotonated form and contains -2 charge
the NH3+ group of N terminal and side chain of lysine is present in protonated form and contain charge +2 (+1 of amino terminal and +1 for side chain)
Total charge on peptide =-1-1+1+1 = 0
Ans e- Charge on peptide at pH =14
COO- is present in its deprotonated form as explain previously pH is greater than the pKa. Charge due to both COO- group = -1-1 =-2
NH3 group of N terminal of peptide chain also present in ionized form as pKa for NH3+ is 9.83 which is lower than the pH
Side chain of lysine is also loose its proton as pH>pKa (10.53)
So charge due to amino group is zero, total charge on protein = -2
C,D, and E i need help with. 17. The following peptide forms part of Human Hemoglobin...
PLEASE HELP OCHEM QUESTION 1. In the following protein, identify the type of bonding or interaction that is responsible for holding the two peptide chains together at each amino acid pair, above (A) and below (B). Gly - Ala - Ser - Cys - Val - Asp - Leu - Thr - His - Ile-Tyr-Glu - Phe - Lys - Cys - Met - Asn Val - Leu -Gin-Cys - Pro-Lys - Met - Tyr - Asp -Phe-Asn-Lys - Ile...
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How many amino acids are there in the disease causing variant of the Amyloid-beta (Ab) peptide? Determine which of these four peptides is most likely to become a beta sheet. Lys-Thr-Val-Ile-Trp-Pro-Phe-Tyr-Ile-Gln-Ile-Gly Arg-Ser-Tyr-Glu-Gly-Leu-Lys-Arg-Ile-Ala-Glu-Ser Ala-Glu-Met-Leu-Gln-Lys-Arg-Gly-Cys-Gly-Asp-Glu Met-Leu-Lys-Ala-Ser-Ala-Leu-Glu-Lys-Leu-Ser-Glu
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5. Consider the following peptide: His-Ser-Gln-Gly-Thr-Phe-Thr-Ser-Asp-Tyr-Ser-Lys-Tyr-Leu-Asp-Ser-Arg-Arg-Ala-Gin- Asp-Phe-Val-Gln-Trp-Leu-Met-Asn-Thr a. What are the fragments, if it is cleaved by trypsin? b. What are the fragments, if it is cleaved by chymotrypsin? c. What are the fragments, if it is cleaved by pepsin?
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What fragments will be obtained by a trypsin hydrolysis of the following octapeptide? Ala-Val-Trp-Lys-Phe-Gly-Arg-Met A) Ala-Val-Trp-Lys-Phe and Gly-Arg-Met 3) Ala-Val-Trp-Lys-Phe-Gly and Arg-Met - Ala-Val-Trp-Lys and Phe-Gly-Arg and Met ) Ala-Val-Trp-Lys and Phe and Gly-Arg and Met ) Ala-Val-Trp and Lys-Phe-Gly and Arg-Met Bradykinin is a nonapeptide, Arg-Pro-Pro-Gly-Phe-Ser-Pro-Phe-Arg. In addition to one mole of Arg, what peptides are present after hydrolysis of bradykinin with chymotrypsin? A) Arg-Pro-Pro and Gly-Phe and Ser-Pro-Phe B) Pro-Pro-Gly and Phe-Ser-Pro-Phe-Arg C) Arg-Pro-Pro-Gly-Phe and Ser-Pro-Phe ?) Arg-Pro-Pro-Gly-Phe-Ser...
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please explain each question thoroughly. thanks Question 3: Arg-Cys-Met-Ala-Cys-Gly-Arg-Pro-Asn-Tyr-Leu-Trp-Ala-Ile-His-Phe-Ser-Cys-Lys a. What would happen if this peptide were to be incubated with dinitrofluorobenzene (FDNB) followed by 6M HCl hydrolysis at 1100C for 24 hrs. What labeled product(s) would be detected? Consider the following pepide: What would happen if the peptide were treated with CNBr? What would the products be? Why? b. What would happen if the peptide were treated with chymotrypsin? What would the c. products be? Why? Arg-Cys-Met-Ala-Cys-Gly-Arg-Pro-Asn-Tyr, Leu-Trp, Ala-Ile-His-Phe,...
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