The heat of formation(ΔHfO) for AsCl3(l) is -305.0 kJ/mol, and ΔHO = -548.8 kJ for the following reaction:
2 As (s) + 3 Cl2 (l) --> 2 AsCl3 (l)
Find the heat of vaporization for Cl2. (Vaporization is a phase change from liquid to gas, so the heat of vaporization would be ΔHO for the process Cl2(l) --> Cl2(g).)
Given that 2 As (s) + 3 Cl2 (l) --> 2 AsCl3 (l)
ΔHfo [AsCl3 (l) ]=-305.0 kJ/mol
ΔHo = -548.8 kJ
We know that ΔHfo [As(s) ]= 0
ΔHo = ΔHfo(products) - ΔHfo(reactants)
ΔHo = 2x ΔHfo [AsCl3 (l) ] - { 3xΔHfo [Cl2(l)]+ ΔHfo [As(s)] }
-548.8 kJ = 2x -305.0 kJ/mol - { 3xΔHfo [Cl2(l)]+ 0 }
-548.8 kJ = -610.0 kJ/mol - { 3xΔHfo [Cl2(l)] }
3xΔHfo [Cl2(l)] = -610.0 kJ/mol + 548.8 kJ
ΔHfo [Cl2(l)] = -20.4 kJ
Heat of vaporization for Cl2
Cl2(l) --> Cl2(g)
From above, ΔHfo [Cl2(l)] = -20.4 kJ
We know that ΔHfo [Cl2(g)] = 0
Heat of vaporization ΔHo = ΔHfo [Cl2(g)] - ΔHfo [Cl2(l)]
= 0 - { -20.4 kJ }
= + 20.4 kJ
ΔHo = +20.4 kJ
Hence, heat of vaporization for Cl2 = +20.4 kJ
The heat of formation(ΔHfO) for AsCl3(l) is -305.0 kJ/mol, and ΔHO = -548.8 kJ for the...
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