Question

Part A The Henry's law coefficient of 1-butanol at 298 K is 9 26 bar. Calculate the vapor pressure (in bar) of 1- butanol over a 0,0240 M aquoou moles of water in L at 298 K olution. There are 55.3 Express your answer to three significant figures and include the appropriate units. PB bar Submit My Answers Give Up de Continue at (b

Answer 1

According to Henry's Law, P_B=K_Hx_B,

where_, P_B is vapour pressure of 1-butanol, K_H is Henry's Constat, x_B is mole fraction of 1-butanol

now convert 0.0240 M into moles as M=no of moles/L

0.0240=no of moles/1L

=0.0240 moles

now, x_B=0.0240 moles /0.0240+55.3 moles

=0.0240/55.324

=0.00043

now, P_B=9.26 bar X 0.00043

=0.00398 bar