Question

Find i1(t) and iz(t) for t> 0 in the given circuit. Assume L4 = 3.0 H and L2 = 4.4 H. 5A 60 2012 t=0 / 5n Lş Leo The current i1(t) = The current iz(t) = A for t> 0. A for t> 0. e-t1

Answer 1

solutions 5A on to s 201 Listwa 52 Given, the switch L=3.0H it open and and L2 = 4.4 H inductor short circuited. At t=0, $51 201 5n 0 {br 20 from nodal analysis, -5+ y + " + = 20 ¥ + UUT V = 5 + 5y = 5 + +++ 5 RV +3V = 5 5 5V = x V = 12 volts Thus, 1,- - = 2.84A iz - y = 2 = 0.6 A Now, the current can be written as in initial conditions li(0) = 2.4 A (0-) = 0, 6 A At to the switch is closed and 1=5A and R=62 get shorted X₂ Thus, this sonce free circuit 34.44 VW 201

and the current will be -RT 2 Pict = to eft a {icts = I, %} Y- where, t= Ļ and Z = 0.22 200 g = = 0.6 and Ez a leve a lot = 0.22 the current is given as Thus, i CH = 204 è t/0.6 iz C) = 0.6 e-t/0.22 - and