The free energy of formation for C10H24(g) is 138.470 kJ/mol. What is the equilibrium constant at...
The free energy of formation for C10H24(g) is 138.470 kJ/mol. What is the equilibrium constant at 25.0?C for its formation?
Homework Answers
We know that the Gibbs free energy change
Where R =Universal gas constant, T is temperature in Deg.K and K is equilibrium constant
l
lnk= -138.47/(0.00831*298) =-138.47/2.4768 = -55.9163
K= 5.198X10-25
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The free energy of formation for C10H24(g) is 138.470 kJ/mol.
What is the equilibrium constant at...
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