Question

Sphe p herica and Co we Too con and s P C o radins ao ) | Ca) Where s al he chaege o hese o ce) whst is the electeie Potential V eve shell radii bo Charge Q n SP and 7nSee her e shell. conductors 7Q 了 Cb) whatis Eer ety w he re

Answer 1

Radius of the sphere is 90 and charge on the sphere is Q charge on the shell is 7Q. (a) We know that electric field inside the conductor is zero. So when we give the charge to any conductor it is always distribute on the surfaces of the conductor. Charge will be distribute on the surface of the conductor. 7Q + Q = 8Q charge Q is distributive in the surface of the sphere and due to induction -Q charge will be induced on the inner surface of the shell, and electric field inside the conductor is always zero that is charge on the outer surface of the shell is 7Q + Q = 8Q. \r\n (b) first we find the electric field at a distance r from the center such that r < a_0 from gauss law contourintegral E^vector dA^vector = Q_inclosed/epilson_0 charge is distributed on the surface that is charge in closed in the Gaussian surface is Q_incloser