Pv | Loan amount | $900,000 | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Rate | Monthly interest rate=(3.6/12)%= | 0.003 | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Nper | Number of months of payment | 480 | (40*12) | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
PMT | Monthly Payment | $3,540.70 | (Using PMT function of excelwith Rate=0.003, Nper=480, Pv=-900000) | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
AMORTIZATION SCHEDULE | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
A | B | C=A*0.003 | D=B-C | E=A-D | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Month | Beginning Principal | Monthly Payment | Interest | Reduction in principal | Ending Principal Balance | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
1 | $900,000 | $3,540.70 | $2,700.00 | $840.70 | $899,159.30 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
2 | $899,159.30 | $3,540.70 | $2,697.48 | $843.22 | $898,316.08 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
3 | $898,316.08 | $3,540.70 | $2,694.95 | $845.75 | $897,470.32 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
4 | $897,470.32 | $3,540.70 | $2,692.41 | $848.29 | $896,622.03 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
5 | $896,622.03 | $3,540.70 | $2,689.87 | $850.83 | $895,771.20 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
6 | $895,771.20 | $3,540.70 | $2,687.31 | $853.39 | $894,917.81 |
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Payment During eleventh year (Month121 to 132) | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Total Payment To Principal | $14,693.08 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
Total Payment To Interest | $27,795.32 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
1. Callan Muffley borrows $900,000 to buy a house. The stated annual interest rate on the...
Brian borrows $5,000 from a bank at 8 percent annually compounded interest to be repaid in five annual installments. Calculate the principal paid in the third year. a. Calculate the annual, end-of-year loan payment. b. Prepare a loan amortization schedule showing the interest and principal breakdown of each of the three loan payments. Amortization Schedule End-of-year Beginning-of-year principle Loan Payment Loan Payment End-of-year balance Interest Paid Principal Paid 1 5,000 2 3 c. Explain why the interest portion of each...
A homebuyer borrows 400,000 to be repaid over a 20 year period with level monthly payments beginning one month after the loan is made. The interest rate on the loan is a nominal annual rate of 12% convertible monthly. Find: a. the monthly payment b. the total principal paid on the loan over 20 years c. the total interest paid on the loan over 20 years d. the loan balance after 15 years e. the total principal paid on the...
Given the annual interest rate and a line of an amortization schedule for that loan, complete the next line of the schedule. Assume that payments are made monthly. Annual Interest Rate Payment $524.49 Interest Paid $43.29 Paid on Principal $481.20 Balance $8,040.03 out the amortization schedule below. Payment Balance Annual interest Rate 6.1% Interest Paid $43.29 Paid on Principal $481.20 $8.040.03 $524.49 $ 524.49 Round to the nearest cent as needed.
A homebuyer borrows 400,000 to be repaid over a 20 year period with level monthly payments beginning one month after the loan is made. The interest rate on the loan is a nominal annual rate of 12% convertible monthly. Find using mathematical formulas: a. the total principal paid on the loan over the first 15 years b. the total interest paid on the loan over the first 15 years
aSuppose you bought a house and took out a mortgage for $100,000. The interest rate is 3%, and you must amortize the loan over 10 years with equal end-of-year payments. A. Calculate the mortgage payment using the Excel function Rate Nper PV FV Payment B. Set up an amortization schedule that shows the annual payments and the amount of each payment that repays the principal and the amount that constitutes interest expense to the borrower and interest income to the...
Problem 2 (Required, 25 marks) Tina borrows an amount $500000 from the bank and agrees to repay the loan by 4n level monthly payments (with amount X) made at the end of every month. The first repayment will be made 1 month after today. You are given that • The loan charges interest at an annual nominal interest rate 5.9% convertible continuously. • The outstanding balance at 25th repayment date is OLBs = 397021.93. (a) Calculate the interest due and...
Ben Thenking wants to borrow $300,000 to buy a house. He plans to live there for exactly 5 years before selling the house, repaying the lender the balance and moving. Ben is considering a 30 year fully amortizing fixed rate mortgage with monthly payments. The banker shows Ben three loan options: (1) A loan with a 5% annual interest rate which requires Ben to pay 2 points up front, (2) the same terms as (1), but the loan principal is...
Loan amortization schedule Personal Finance Problem Joan Messineo borrowed $46,000 at a 4% annual rate of interest to be repaid over 3 years. The loan is amortized into three equal, annual end-of-year payments Calculate the annual end of year loan payment b. Prepare a loan amortization schedule showing the interest and principal breakdown of each of the three loan payments. c. Explain why the interest portion of each payment declines with the passage of time. a. The amount of the...
Chrome Co. borrows $1,665,000 at an interest rate of 7.32% APR monthly with equal monthly payments of $15,265 and a 4 year stop. a) What is the loan balance at the end of month 36? b)What is the balloon payment due, after the regular monthly payment, at the end of year 4? Please show work
Construct an amortization schedule for a $1,000, 10% annual rate loan with 3 equal annual payments. Step #1: Find the required annual payment on the loan. Step #2: Complete the amortization table for the loan. (4) = (2)-(3) (5) = (1)-(4) (3) = (1) * interest rate INTEREST EXPENSE PAYMENT YEAR PERIOD BEGINNING BALANCE PRINCIPAL REPAYMENT ENDING BALANCE