We know that the collision occurs in round 1 so, the probability of transmission in round 1 is zero.
So, The probability that the contention ends in round k is :-
The mean number of rounds per contention period is nothing but the expectation which is given by :-
Two CSMA/CD stations are each trying to transmit long files. After each frame is sent, they...
Two CSMA/CD stations are each trying to transmit long (multiframe) files. After each frame is sent, they contend for the channel, using the binary exponential backoff algorithm. What is the probability that the contention ends on round k, and what is the mean number of rounds per contention period? Please type answer, please do not hand write. Thank you
suppose two devices using CSMA/CD and the binary exponential backoff algorithm have just sent transmission that have each experienced collision Twice. what is tye probability that both devices will transmit successfully during the bext two time slots where n=3.