Calc question
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Find a function F(x) that satisfies the initial value problem: dF dx = 1 − cos(2x) + e 0.5x , and F(0) = 4. Suggestion: Try to “guess-and-check” to find an antiderivative.
Calculus
Find an antiderivative of the function f(x) = 2x® (3x? +4)? What is a possible antiderivative of the given function? O A. F(x) = 6 (3x® + 4) 3 OB. F(x) = (3x® + 4) 3 OC. F(x) = (3x +4) 3 OD. F(x) = § (3x?+4) 3
Find the supply function x = f(p) that satisfies the initial conditions. dx 16 x = 180 when p = $3 dp p - 3 X =
(3) Find the function x(t) that satisfies the initial value problem x"(t) = te2t, x(0) = 0, z'(0) = 1
(1) Solve the initial Value Problem (IVP): 2x+1 f'(x) = — ; f(0) = 1. x²+1 DE): frm=2* 31 (a) First, solve the differential equation (DE): f'(x) = 2x+1 — x2 + 1 1 2x+1 Hint: - x2+1 2 x 1 - + - x?+ 1 x2 + 1 2 x Guess a function whose derivative is x2 + 1x2+1 Gues humaian whose centraline a creative 1.a, tratan antarane element ;) 1 2 x 1 i.e., find an antiderivative of...
Find the solution to the initial value problem: dy dy/dx=x^ 2√1 + x^3/1+cos y y(0)=2 the 1+x^3 is all in square root.
Problem 5: Evaluate log(x) Jo 4+2 0 3. Show that 2x cos(e) Jo 1-cos(0)
Problem 5: Evaluate log(x) Jo 4+2 0 3. Show that 2x cos(e) Jo 1-cos(0)
Find the solution of the given initial value problem in explicit form. y'=(1-13x)y^2 , y(0)=-1/4 I'm in differential equations and it has unfortunately been some time since I took Calc II. it appears that I'm getting stuck near when one would integrate y'*y
20. The function f(x)=e satisfies the hypotheses of the Mean Value Theorem on the interval [0, 16] Find all values of c that satisfy the conclusion of the theorem. a. - Sin 2e b. Sin c. -Sin d. Sin 2e2
f""(x) = 4+cos(x), f(0)=-1, f(3pi/2)=0
f(x)=?
Find f. F"(x) = 4 + cos(x), f(0) = -1, f(31/2) = 0 Flx) = 2x2 Viewing Saved Work Revert to Last Response Submit Answer