Question

Giving an optical system compose of two lens system. Lens 1 focal length = 10-cm, Lens 2 focal length = 5-cm. The distance between the two lenses L = 50-cm. An object is 30 meter away from Lens 1, with height of 10-cm (a) Setup the equation, that solve the image location and the magnification, at each lens? (b) Solve the image location, magnification, and height at each lens? (c) If you want the object to have a final magnification of 1, m = 1. What will object location, and the L distance between lenses have to be.? (d) If the object is 10000 meters away what will the image distance be for lens 1?

Answer 1

f_1 = 10 cm f_2 = 5 cm lens I u = -3000 cm. f = + 10 lens formual 1/v - 1/u = 1/f 1/v = 1/u + 1/f v = uf/u + f = (- 3000) times (10) /10 + (- 3000) = + 10.0334. for lens (II) u = -(50 - 10.0334) = -39.97 gf = + 5 v = uf/u + f = (- 39.97) times (5) /(- 39.97 + 5) = 5.72 cm. m_II = v/u = -5.72/39.97 = 0.43 m_I = -10.0334/3000 = 3.34 times 10^- 3 (b) h_i /h_0 = mI implies h_i = m_I times (10 cm) = 0.0334 cm. m_II = h_i^' /h_0^' = 0.0334 times 0.43 = 0.0144 cm. (c) There are many possible locations m_I middot m_II = 1 object at 2/image at 2 f same size object at 20 cm in front of lens I &