Question

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Beginning from the first set of parents, let us try to determine the genotype of all sets.

Parents 1: The father can be IBIB or IBi and the mother can be IAIAor IAi. For the MN group, The father is NN and the mother is MN. So, their children can of A, B, AB or O blood type and of either MN or N blood group.

Parents 2: The father can be IAIA or IAi and the mother can be IAIAor IAi. For the MN group, The father is NN and the mother is also NN. So, their children can of A or O blood type and of N blood group.

Parents 3: The father can be IAIAor IAi and the mother is IAIB. For the MN group, both the parents are of MN type. So, their children can of A, B, or AB blood type and of either M, N or MN blood group.

Parents 4: The father is ii and the mother is IAIAor IAi. For the MN group, both the parents are of MM type. So, their children can of A or O blood type and of M blood group.

Amongst the given set of children only one has the N type blood group. So this child (a) definitely belongs to the parents who can have children with only N blood group i.e. Parents 2.
For the remaining 3 cases (b, c and d), we want parents with possibility of giving children of M type blood for children (c) and (d). Parents 1 cannot give an offspring with M type blood group, so it has to be matched with child (b) where it can easily give AB and MN blood types.
For child (d), Only parents 4 are a match because that is the only set of parents from the remaining parents which can have a child with O blood group.
That leaves parents 3 to give birth to child (c) with A blood group and M blood type and it is possible.

So, 1- b, 2- a, 3-c, 4-d

Add a comment
Know the answer?
Add Answer to:
The ABO and MN blood groups are given below for four sets of parents (1 to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • ABO BLOOD TYPE The ABO blood groups in humans are determined by multiple alleles. A single...

    ABO BLOOD TYPE The ABO blood groups in humans are determined by multiple alleles. A single gene can exist in any of three allelic forms: 14, Bor i. This inheritance of the ABO blood type displays codominance as well as complete dominance. The two codominant genes A and B code for production of antigen A and antigen B on the surface of red blood cells, and are both completely dominant to the recessive allele i. The chart below shows the...

  • Analyzing Genetic Data A. ABO Blood Group The human ABO blood group is an example of...

    Analyzing Genetic Data A. ABO Blood Group The human ABO blood group is an example of how three alleles that control a trait may interact. In this case, two of the alleles are codominant and one is recessive to the other two. The table below lists the phenotypic and genotypic data for this trait. Blood Type Phenotype Type A Type B Type AB | Type 0 Possible Genotype Ilori Pori | IAI 1. List the three alleles that control expression...

  • A gene for the MN blood group has codominant alleles M and N. If both children...

    A gene for the MN blood group has codominant alleles M and N. If both children in a family are of blood type M, which of the following situations is possible? OA) Each parent is either Mor MN. OB) Both children are heterozygous for this gene. OC) Each parent must be type M. OD) Neither parent can have the N allele.

  • The ABO blood groups.There are three main alleles in the ABO blood group system -...

    The ABO blood groups.There are three main alleles in the ABO blood group system - IA, IB, and i. We've talked about the ABO system in class, you can find a brief explanation below and here.The I gene encodes for a glycosyltransferase that modifies at the H antigen.The glycosyltransferase encoded by IA adds an 'A' sugar group to antigen H, the glycosyltransferase encoded by IB adds a 'B' sugar group and i encodes an inactive glycosyltransferase that leaves the H...

  • 8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and...

    8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and two men Y and Z). The analysis is limited to the ABO and Rh blood group systems. Using the space below, and assuming that only YorZ could be the biological father, assign each child to his/her possible father. You can use either Punnett squares for each trait, or the process of Mother Possible Fathers Children Possible father for each child elimination. There may be...

  • There are three main alleles in the ABO blood group system - IA, IB, and i....

    There are three main alleles in the ABO blood group system - IA, IB, and i. We've talked about the ABO system in class, you can find a brief explanation below and here. The I gene encodes for a glycosyltransferase that modifies at the H antigen. The glycosyltransferase encoded by IA adds an 'A' sugar group to antigen H, the glycosyltransferase encoded by IB adds a 'B' sugar group and i encodes an inactive glycosyltransferase that leaves the H antigen...

  • 2 points (IV.C.2) You are working as a genetic counselor and after completing a family pedigree,...

    2 points (IV.C.2) You are working as a genetic counselor and after completing a family pedigree, you observe that eight of a couple's thirteen children have a disease. Some of the couple's grandchildren also have the disease. However, no grandchildren with two unaffected parents have the disease. What type of allele causes this disease? lethal O dominant Y chromosome о recessive (IV.C.1) You are studying two different genes; each gene is on its own chromosome. Gene H codes for height...

  • I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that...

    I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...

  • The population of a particular country consists of three ethnic groups. Each individual belongs to one of the four majo...

    The population of a particular country consists of three ethnic groups. Each individual belongs to one of the four major blood groups. The accompanying joint probability table gives the proportions of individuals in the various ethnic group-blood group combinations Blood Group O A B AB 1 0.082 0.111 0.013 0.004 Ethnic Group 2 0.130 0.141 0.018 0.001 3 0.215 0.195 0.070 0.020 Suppose that an individual is randomly selected from the population, and define events by A type A selected),...

  • Select from the terms below to answer the question below Each term is used once. A)...

    Select from the terms below to answer the question below Each term is used once. A) Codominance B) Incomplete Dominance C) Complete Dominance D) Pleiotropy E) Genetic Heterogeneity F) Epistasis G) Epigenesis            True breeding “long” radishes were crossed with true breeding “round” radishes.The offspring of this cross resulted in 100% “oval” radishes. This type of inheritance is most consistent with _________ Marfan syndrome is caused by an autosomal dominant gene that has multiple phenotypic effects such as lengthened long...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT