YOUNG'S MODULUS = STRESS / STRAIN
YOUNG'S MODULUS IS APPROXIMATELY EQUAL TO 5745.66 MPa
Q1. A circular rod of 12 mm diameter was tested for tension. The total elongation on a 300 mm length was 0.22 mm under a tensile load of 17 KN. Find the value of E. (2.5 Marks) Answer: Q2. A prismatic bar has a cross section of 25 mm x 50 mm and a length of 2m under an axial force of 90 KN. The measured elongation of the bar is 1.5 mm. Compute the tensile stress and strain in...
1. A 520 mm long and 3.3 mm diameter mild steel rod undergoes a stress test. A tensile force of 30200 N is applied and the rod extends by 0.05 mm. (i) Calculate the nominal stress. (ii) Calculate the nominal strain. (iii) Calculate Young's Modulus. (Answer format: Standard form, No thousands separator, Two decimals, Optional Unit if any)
3. A square rod of 500 mm long with a width of 10 mm is subjected to a load of 40000 N., The stress-strain behavior is shown in the Figure below. Based on the information, please answer the following questions: (Note: Pa = N/㎡, J = Nm) (a) Compute the applied stress (5 points). 70 Tensile strength 450 MPa (65.000 ps) -60 400 103 ps MPa 40厂 50 300 40 Yield strength30 250 MPa (36.000 ps) 200 100 20 10...
A 25mm diameter steel rod 1.5m long is being used in a rigid structure. For this steel the Ultimate Tensile Stress is 410 MPa Young’s Modulus is 200 GPa The rod is to be subjected to a tension load of 40 kN. Design requirements are that the rod cannot extend by more than 0.5 mm and that there is a Factor of Safety of 5 for the tensile stress. Determine whether or not the rod is adequate for the task:...
Engineering materials
b) A mild steel rod of 4 cm diameter was tested for tensile strength with the gauge length of 60 mm. The following observations were recorded: Final length = 9 cm; Final diameter = 8 mm; Yield load – 5.4 kN and Ultimate load – 8.1 KN. (4 Marks) Calculate 1. Yield stress (1 Mark) 2. Ultimate tensile stress (Mark) 3. Percentage reduction in area. (1 Mark) 4. Percentage elongation (IMark)
Identify the material. that fits the stress-strain
curve.
A)
MILD STEEL
Yield Strength: 30 kN, Ultimate Strength: 40 kN, Young Modulus:
30/0.7 kN/mm = 43 kN/mm
B)
ALUMINUM
Yield Strength: 20 kN, Ultimate Strength: 26 kN, Young Modulus:
20 kN/mm
C)
CAST IRON
Yield Strength: N/A, Ultimate Strength: 20 kN, Young Modulus:
20/0.4 kN/mm = 50 kN/mm
D)
COPPER
Yield Strength: 30 kN, Ultimate Strength: 35 kN, Young Modulus:
30 kN/mm
Instructions CLI Tesile TesTeR Test Specimens Material - Mild...
(GPa) A cylindrical machine part 250 mm long with a diameter of 10 mm is subjected to an axial load of 28,500 N. Using the list of materials shown in the table below, answer questions 1 through 2. Yield Strength Young's Modulus Material [MPa] Density (g/cm] Aluminum alloy 255 70 2.75 Steel alloy 400 207 7.85 Titanium alloy 800 110 4.50 Copper alloy 250 110 8.50 Brass alloy 340 100 8.40 1. If the elongation is not to exceed 0.6...
A 60-m-long steel wire is subjected to a 6.5-kN tensile load. It is given that E = 200 GPa and the length of the rod increases by 48 mm. Determine the smallest diameter that can be selected for the wire.
question 6
of 25 mm is pulled in tension with a 44,500 N force producing only elastic detormation . What is oreonding strain and the length between the gage marks when subjected to this force? Given: elastic modulus of copper is 105 GPa. 5. A 10-mm diameter bar of 1040 carbon steel is subjected to a tensile load of 50,000 N, taking it beyond its yield point. Calculate the elastic recov removal of the tensile load. Given: elastic modulus of...
. Design a cotter joint to connect two mild steel rods. The joint is subjected to 90 kN tensile forces. The allowable limits of tensile, shear and crushing strengths are 160 N/ mm 100 N/mm and 200 N/mm respectively