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10. The population average for SAT score is 1020, with a population standard deviation of 100 a. What is the standard deviati

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10. \small \bar{x} = 1020

\small \sigma = 100

a) Standard deviation of the distribution of \small \bar{x} if sampling size, n = 64 is given by,

\small \sigma_{\bar{x}} = u

= 100/64

= 12.5

b) \small \mu_{\bar{x}} = \small \bar{x} = 1020

\small \sigma_{\bar{x}} = 12.5

P(\small \bar{x} < A) = P(Z < (A - \small \mu_{\bar{x}} )/\small \sigma_{\bar{x}})

P(sample mean within 10 points of the population mean) = P(1010 < \small \bar{x} < 1030)

= P(Z < (1030 - 1020)/12.5) - P(Z < (1010 - 1020)/12.5)

= P(Z < 0.8) - P(Z < -0.8)

= 0.7881 - 0.2119

= 0.5762

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