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1)

Suppose that X is a uniform random variable on the interval (0, 1) and let Y = 1/X. a. Give the smallest interval in which Y2)

Suppose that X ~ Bin(4, 1/3). Find the probability mass function of Y = (X – 2)2. a. List all possible values that Y can take3)

Let X ~ Unif[–1,5), and let Y = X2. Compute the probability density function of Y. The answer is a piecewise function with th4)

Suppose that X ~ Exp(m) and Y = ln X. a. Compute the cumulative distribution function of Y. (It will be in terms of the const5)

Suppose that X is a discrete random variable with probability mass function given by P(X = -1) = P(X = 0) = }, P(X = 2) = à P

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Answer: 1) Given that. a) fx(x) = { o elsewhere CDF of : Ex(x) = f S FX(t) at dt-X co ;x<o = 2 x ; 0<x<I I; XZ :. Y=la sincefyly)= 1- fx(²4) 1-Yy; kyco .: fyly) = {1- Yy; kyeo probability density function of y-fy Cy) =day [fy (y)] = /dy (1-²y =aldy

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