Question

USE MATLAB TO SOLVE THIS PROBLEM:

Use a primary function that uses a subfunction to compute the zeros of the function 3.23 – 12:22 – 33.+80 over the range -10 sxs 10.

Answer 1

%MATLAB Code

lb = -10; % Set a lower bound for the function.
ub = 10; % Set an upper bound for the function.
x = NaN*ones(100,1); % Initializes x.
starting_points=linspace(-10,10,100);
for i=1:100
% Look for the zeros in the function's current window.
x(i)=fzero(@(x)(3*x^3-12*x^2-33*x+80), starting_points(i));
end
x_unique=x(diff(x)>1e-12)

Paste this matlab code in the mall ab script 16 = -10 ub= 10 x = Nant ones (200, 1); Starting points = line space (-10,10,100); for is 1:100 occio - Azero (@(o) ( 3* DA (3)-12* OPR) - 33* (CH480), I starting points (:)); end - unique = x ( diff Car) > 11-12)