H2(g) + I2(s) → 2HI(g) Given an initial mass of 15.28 g H2, an excess of...

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H2(g) + I2(s) → 2HI(g) Given an initial mass of 15.28 g H2, an excess of...

H2(g) + I2(s) → 2HI(g) Given an initial mass of 15.28 g H2, an excess of I2, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of HI produced by the reaction.

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Answer 1

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Solna Crivent H2 + Iz 2HI. initial mass of H2 = 15.289 i moles of H2 = 15-28 37.64 molee from a moles of H₂ = 2 moles of HI w

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H2(g) + I2(s) → 2HI(g) Given an initial mass of 15.28 g H2, an excess of...

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H2(g) + I2(s) → 2HI(g) Given an initial mass of 15.28 g H2, an excess of...