This is an mathematical problem. It can be solved as shown
X+2 = 6
X = 6-2
X = 4
Hence, Value of X is 4
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6. >>x=[1 2 4 6 12]; >m mean(x) > var(x)
Complete the description of the piecewise function graphed below. 6 2 -7 -6 -5 -3 -2- 34 if -6 x< - 3 Preview { f(x) if -3 < x< 2 { Preview if 2 < x < 6 Preview
Complete the description of the piecewise function graphed below. 6 2 -7 -6 -5 -3 -2- 34 if -6 x
6. Where are the following functions discontinuous? a) f(x) = x+2) x+2 (x+2)x b) f(x) = 21
Results for this submission Entered Answer Preview Result (3/2)+(6/pi)*cos(x) e + cos(2) correct (3/2)+(6/pi)*cos(x)-(2/pi)*cos(3*x) 3 6 st-ce 2 s(3x) correct (3/2)+(6/pi)*cos(x)-(2/pi)*cos(3*x)+(6/5)*pi*cos(5*x) it coule) = _ cou(30) + * cos(52) incorrect A correct f(x) f(x) correct At least one of the answers above is NOT correct. 1 (1 point) (a) Suppose you're given the following Fourier coefficients for a function on the interval (-1,7): a 3 6 6 6 = , ai = –, az = -2,25 = = and 22,...
Solve for x. 0 -2 x – 6 -23 1 = 0 x +4 -2 -5 X - –6 X = Submit Answer Tries 0/10
6. If 3x – 3 5 f(x) < x2 – 3x + 6 for x 2 0, find lim f(x). X-3
How do I solve this x^2(x+1)-x(x+1)-6(x-1)=0 no idea how to make -6(x-1) to be 6(x+1) and factor out it. Be able to follow the comment
Homework Algebra 2 5. V2x + 12 = x + 2 6. Vx + 6 – x = 4 I 7. 4(x – 5)ź = 12 8. 2(x – 50)5 = -10
What is the composition(fog)(x) when f(x) = 2x+6 and g(x)=x2-1, before simplifying? a.(fog)(x)=x2-1+2x+6 b.(fog)(x)=(2x+6)2-1 c.(fog)(x)=2(x2-1)+6 d.(fog)(x)=(2x+6)(x2-1)
Below is the graph of y=f(x). Graph y = -f(x). r -6 -2 2 4 6